\begin{align}
\frac{d}{d x} (x^2)^2\Big|_{x=3} = 108
\end{align}
を自動微分で求めてみましょ・・・というだけ。
[TensorFlow]
x = tf.constant(3.0) with tf.GradientTape() as t: t.watch(x) y = x * x z = y * y dz_dx = t.gradient(z, x) print(dz_dx)
tf.Tensor(108.0, shape=(), dtype=float32)
[PyTorch]
x = torch.tensor(3.0, requires_grad=True) #x.requires_grad_(True) y = x * x z = y * y z.backward() dz_dx = x.grad print(dz_dx)
tensor(108.)